Decoding V77873

The decoding of a natural number $n$ is a string of characters such that every two digits of $n$ represent a character. For example, the decoding of $n = 6568$ is AD, because the ASCII code of the character A is 65 and the ASCII character of the character D is 68. Notice that $n$ has two groups of two digits: $65$ and $68$. Another example: the decoding of $65666768$ is ABCD, since $n$ is composed of $65$, $66$, $67$, and $68$.

It is necessary to implement the recursive function void decodificacio(int) with the following specification:

PRE: The input is an integer $n$ such that:

1. $n \geq 65$

2. $n = d_1 d_2 d_3 d_4 \dots d_{m-1} d_m$.

3. $m$ is even

4. for any pair of digits $d_i d_{i+1}$ ($i$ odd) we have that $65 \leq d_i d_{i+1} \leq 90$.

POST: writes the decoding of $n$ to the output channel cout.

Observation

Only recursive solutions are accepted.

IMPORTANT: You only need to submit the requested function, and possibly other necessary actions and functions. However, you must keep the type definitions and #includes.

Input

The input consists of a natural number $n \geq 65$ such that $n = d_1d_2d_3d_4 \dots d_{m-1}d_m$ $m$ is even and for any pair of digits $d_i d_{i+1}$ such that $i$ is odd, we have that $65 \leq d_i d_{i+1} \leq 90$.

Output

For each integer $n$, its decoding.