For every natural n, let X(n) be the smallest natural m such that m ends with n and m is a multiple of 7. For instance, X(1) = 21, X(2) = 42, X(3) = 63, …, X(7) = 7, X(8) = 28, X(9) = 49, X(10) = 210, X(11) = 511, …Let S be the infinite concatenation of X(i) for every i ≥ 1, that is, S = 21426314355672849210511.... Which is the i-th digit of S?
Input
Input consists of several cases, each with a natural i between 1 and 1015.
Output
For every i, print the i-th digit of S (starting at one).
Input
1 2 3 4 13 14 15 18 19 20 1000000000000 1000000000000000
Output
2 1 4 2 7 2 8 2 1 0 4 5