Old cassette player (2) P52998


Statement
 

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Consider an old cassette player, whose only working buttons are “play” and “rewind”. You have just one cassette, which you always keep completely rewinded. So, when you want to listen to a particular song ss, you have to press the “play” button and wait until all the songs stored before ss finish. Afterwards, when ss ends, you always rewind the cassette.

You have nn songs, which you listen to with the same frequency. You know the duration did_i of every song ii. Assume that the cassette is long enough to store all your songs. Your goal is to choose the order to store the songs so as to minimize the expected time to listen to a desired song.

Input

Input is all natural numbers, and consists of several cases. Every case begins with nn, which is followed by the durations of the nn songs, all strictly positive. Assume 1n1051 \le n \le 10^5.

Output

For every case, print with four digits after the decimal point the optimal expected time to listen to a desired song. The input cases have no precision issues.

Public test cases
  • Input

    2    6 3
    2    6 6
    4    3 8 1 4
    1    8
    

    Output

    6.0000
    9.0000
    7.2500
    8.0000
    
  • Information
    Author
    Salvador Roura
    Language
    English
    Official solutions
    C++
    User solutions
    C++