Old cassette player (1) P52569


Statement
 

pdf   zip

Consider an old cassette player, whose only working buttons are “play” and “rewind”. You have just one cassette, which you always keep completely rewinded. So, when you want to listen to a particular song ss, you have to press the “play” button and wait until all the songs stored before ss finish. Afterwards, when ss ends, you always rewind the cassette.

You have nn songs, all with the same duration dd. You know that you want to listen to song ii with absolute frequency fif_i. (For instance, if f1=6f_1 = 6 and f2=3f_2 = 3, then you listen to song 1 twice as much as to song 2.) Assume that the cassette is long enough to store all your songs. Your goal is to choose the order to store the songs so as to minimize the expected time to listen to a desired song.

Input

Input is all natural numbers, and consists of several cases. Every case begins with dd and nn, followed by the absolute frequencies of the nn songs. At least one of the frequencies is strictly positive. Assume 1n1051 \le n \le 10^5.

Output

For every case, print with four digits after the decimal point the optimal expected time to listen to a desired song. The input cases have no precision issues.

Public test cases
  • Input

    1 2     6 3
    1 2     6 6
    10 4    3 0 1 4
    100 1   8
    

    Output

    1.3333
    1.5000
    16.2500
    100.0000
    
  • Information
    Author
    Salvador Roura
    Language
    English
    Official solutions
    C++
    User solutions
    C++