simpleAlternatedSum

Implement a RECURSIVE function that, given a positive natural n, returns
the simple altenated sum 1 − 2 + 3 − 4 + … + (−1)^(n + 1) ⋅ n. This is
the header:

    // Pre: n >= 1
    // Post: Returns 1-2+3-4+...+(-1)^(n+1)*n
    int simpleAlternatedSum(int n);

Observation

You only need to submit the required procedure; your main program will
be ignored.

Observation

Note that we are requesting a RECURSIVE solution.

Problem information

Author: PRO1

Generation: 2026-01-25T21:40:46.879Z

© Jutge.org, 2006–2026.
https://jutge.org
